zips together different alignments if their partitions of the text do not match up

master
Isaac Riley 6 years ago
parent 4a56e14484
commit 8446f8e5b8

@ -0,0 +1,42 @@
# -*- coding: utf-8 -*-
def zip_alignments(al0lang0, al0lang1, al1lang0, al1lang1):
if al0lang0==al1lang0:
return al0lang0, al0lang1, al1lang1
else:
new0 = {}
new1 = {}
new2 = {}
k, k0, k1 = 0, 0, 0
while k0<len(al0lang0) and k1<len(al0lang):
if v0==al1lang0[k0]:
new0.update({k:v0})
new1.update({k:al0lang1[k0]})
new2.update({k:al1lang1[k1]})
k0+=1
k1+=1
elif v0==+al1lang0[k1]+' '+al1lang0.get(k1+1, '')
new0.update({k:v0})
new1.update({k:al0lang1[k0]})
new2.update({k:al1lang1[k1]+' '+al1lang0.get(0k1+1, '')})
k0+=1
k1+=2
elif v0+al0lang0.get(k0+1, '')==al1lang0[k1]:
new0.update({k:k:al0lang0[k0]+' '+al0lang0.get(k0+1, '')})
new1.update({k:k:al0lang1[k0]+' '+al0lang1.get(k0+1, '')})
new2.update({k:al1lang1[k1]})
k0+=2
k1+=1
k+=1
return new0, new1, new2
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